The first thing you need to do is calculate how many grams of heavy water are required to produce 1 mole of deuterium. One mole equals the molecular weight in grams divided by 18, which is 2.016 grams per mole. So for every one mole of deuterium produced, it will take 2.016 grams of heavy water to make it happen (or 50 liters). If you have any questions about the heavy water production process, please contact a scientist.

drop of water, drop, impact @ Pixabay

The first thing you need to do is calculate how many grams of heavy water are required to produce one mole of deuterium. One mole equals the molecular weight in grams divided by 18, which is two point sixteen (or 50 liters). So for every one mole of deuterium produced, it will take two point sixteen (or fifty liters) grammes per millilitre of heavy water to make it happen or 15 kilograms per kiloliter. So if your goal is ten moles and we’re using US gallons as our measurement then we’ll need: 100 x 150 = 1500 x 100 = 1500

LEAVE A REPLY

Please enter your comment!
Please enter your name here